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Urgent help..MATHS!!


Fear Deer

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Any of you good souls good in maths?

This is not homework btw

So i decided to try something new-->Study a bit harder to try and get a better mark

and i am trying to solve a problem which has been causing my head to scratch the walls for around 20 minutes... from the time this has been posted!

Please make a clear explanation if you know how to solve it and want to help, its really important to me :)

This is the problem:

Isosceles Trapezium [ABCD]

AB=BC=CD=AD/2

a=area [ABCD]

b=area [ABD]

Exercise: Show that a=(3/2)*b

Image of the trapezium: (not drawn to scale!! remember! ISOSCELES trapezium lol )

2zyzrr8.jpg

 

Btw the trapezium is made out of 2 tiangles

[ABD] and [bCD]

 

Please help me lol

 

il be damn appreciated!

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Is this even possible? AB, BC, and CD are all equal to each other, correct?

 

So how can AD be half of the other lengths? It has to be longer.

 

This thread must be burned! Like every math problem!

 

And yeah, why the hell is a math problem on here! :...:

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most shortcut formulas for calculating the pitch in shapes comes from the simple rule of derivatives.

Lim(->0) [F(Xo+h) - f(Xo)]/h

 

if you look more into derivatives and intergrals you'll be able to calculate those formulas yourself.

 

 

from above B or C draw a line that collides with [AD] at 90 degrees.

that is your height and call that y

 

The formula I was talking about which applies to all trapezoids:

y.[(AD)+(BC)]/2 would give you the area of the trapezoid

and [(AD). y]/2 would give you the area of the triangle

 

domain them random numbers and see the magic happening :P

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most shortcut formulas for calculating the pitch in shapes comes from the simple rule of derivatives.

Lim(->0) [F(Xo+h) - f(Xo)]/h

 

if you look more into derivatives and intergrals you'll be able to calculate those formulas yourself.

 

 

from above B or C draw a line that collides with [AD] at 90 degrees.

that is your height and call that y

 

The formula I was talking about which applies to all trapezoids:

y.[(AD)+(BC)]/2 would give you the area of the trapezoid

and [(AD). y]/2 would give you the area of the triangle

 

domain them random numbers and see the magic happening :P

I have no idea what you just said but I think I did the exact same thing. However I'm not so sure you can just give the sides random values, or can you...? I did, so I got this:

e0sxue.jpg

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I have no idea what you just said but I think I did the exact same thing. However I'm not so sure you can just give the sides random values

-img-

well that's what it looks like when you draw it well done, I was asuming when I said random you'd consider it is an isoscele

looks like you've used hypotenuse technique. Which is alright but I don't really want to deal with roots so I always try to leave them out

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andreaz that looks nice but i think you cant give random numbers

the goal is to prove or demonstrate that "a" can be given as 1.5*"b"

without giving it values, i think 1.5 multiplying by an area makes the area smaller to make a reduction..identical geometry..im not so sure.

I thank you though for helping me ;)

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andreaz that looks nice but i think you cant give random numbers

the goal is to prove or demonstrate that "a" can be given as 1.5*"b"

without giving it values, i think 1.5 multiplying by an area makes the area smaller to make a reduction..identical geometry..im not so sure.

I thank you though for helping me ;)

I made some more calculations with parameters , well b is 3/2 of a in some cases like when the diagnols are perpendicular and a few other situations but it doesn't necessarily means it's 3/2 at all times.

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well that's what it looks like when you draw it well done, I was asuming when I said random you'd consider it is an isoscele

looks like you've used hypotenuse technique. Which is alright but I don't really want to deal with roots so I always try to leave them out

Math lesson in English makes my head hurt :eek:

Andreaz. :omg:

 

 

 

 

 

You can draw basic shapes.

Actually I just drew four lines and they happened to go into a shape! :eek:

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